t^2-7t+11=0

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Solution for t^2-7t+11=0 equation:



t^2-7t+11=0
a = 1; b = -7; c = +11;
Δ = b2-4ac
Δ = -72-4·1·11
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{5}}{2*1}=\frac{7-\sqrt{5}}{2} $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{5}}{2*1}=\frac{7+\sqrt{5}}{2} $

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